In the previous post we talked about several important definitions for angles in flat figures. Now, we deepen the concepts through the properties of angles for applications in flat figures.

angle bisector of an angle

Definition: the angle bisector of an angle is a ray, which starts from the vertex of the angle and divides it into two congruent angles ($\cong$).

Ray b divides angle aOc into two equal angles.
angle bisector produces two congruent angles.
Ampliar figura para ler os detalhes
Ray b divides angle aOc into two equal angles.

From the figure, we notice that

  • $\angle \widehat{aob} \cong \angle\widehat{boc}$
  • Angle $\widehat{aob}$ is congruent to angle $\widehat{boc}$.
  • The ray b is angle bisector of this angle.

Angles opposite the vertex

Definition: two angles are said to be opposite at the vertex if the rays are concurrent.

Two lines intersect and the opposite angles alpha and beta are equal.
The two highlighted angles are opposite at the vertex.
Ampliar figura para ler os detalhes
Two lines intersect and the opposite angles alpha and beta are equal.

From the figure, we notice that

  • $\alpha = \beta$
  • angles $\alpha$ and $\beta$ are equal.

Are the angles the same?

In fact,

drunk walk.

From the post angles in planes we have:

  • angles $C$ and $B$ are supplementary $C + B = 180^\circ$
  • similarly $C$ and $A$ are supplementary $C + A = 180^\circ$
  • With this, we have $C + B = C + A$
  • Logo $B=A$
  • Therefore, the property of angles opposite the vertex holds.

From the figure we obtain:

$$A=B \qquad \text{e} \qquad C=D$$

Two parallel lines cut by a transversal line

From two parallel and distinct lines, cut by another transversal line, we have:

  • we obtain eight angles $a,b,c,d,e,f,h,g$;
  • from the previous section, we observed from the figure that we have two cases of competing lines and they fall into the previous property;
  • these angles are supplementary or congruent;
  • with property opposed by the vertex.
drunk walk.

From the property opposites by the vertex, we obtain:

  • $a=e$
  • $b=f$
  • $c=g$
  • $d=h$

Internal Alternates

drunk walk.
$$ \begin{cases} b=h\\ c=e\\ \end{cases} $$

External Alternates

drunk walk.
$$ \begin{cases} a=g\\ d=f\\ \end{cases} $$

That’s it for now, wait for the next posts.