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Exercícios do capítulo VII — Equações

Em cada equação, pergunte primeiro: a qual equação fundamental ela se reduz? Depois de escrever as famílias de soluções, confira se nenhuma delas anula um denominador da equação original. Equação sen α = sen β 193 Resolva as equações: a) $\operatorname{sen} x = \operatorname{sen}\dfrac{\pi}{5}$; b) $\operatorname{cossec} x = \operatorname{cossec}\dfrac{2\pi}{3}$; c) $\operatorname{sen} x = 0$; d) $\operatorname{sen} x = \dfrac{1}{2}$; e) $\operatorname{sen} x = -\dfrac{\sqrt{2}}{2}$; f) $\operatorname{sen} x = \dfrac{\sqrt{3}}{2}$; g) $\operatorname{sen} x = 1$; h) $\operatorname{sen} x = -1$. Ver a resoluçãoa) $\operatorname{sen} x = \operatorname{sen}\dfrac{\pi}{5} \Rightarrow x = \dfrac{\pi}{5} + 2k\pi$ ou $x = \pi - \dfrac{\pi}{5} + 2k\pi$. $\;S = \left\{x \in \mathbb{R} \;\middle|\; x = \dfrac{\pi}{5} + 2k\pi \text{ ou } x = \dfrac{4\pi}{5} + 2k\pi\right\}$. b) $\operatorname{cossec} x = \operatorname{cossec}\dfrac{2\pi}{3} \Rightarrow \dfrac{1}{\operatorname{sen} x} = \dfrac{1}{\operatorname{sen}\frac{2\pi}{3}} \Rightarrow \operatorname{sen} x = \operatorname{sen}\dfrac{2\pi}{3}$, logo $x = \dfrac{2\pi}{3} + 2k\pi$ ou $x = \pi - \dfrac{2\pi}{3} + 2k\pi$. $\;S = \left\{x \in \mathbb{R} \;\middle|\; x = \dfrac{2\pi}{3} + 2k\pi \text{ ou } x = \dfrac{\pi}{3} + 2k\pi\right\}$. c) $\operatorname{sen} x = 0 = \operatorname{sen} 0 \Rightarrow x = 2k\pi$ ou $x = \pi + 2k\pi = (2k + 1)\pi$. $\;S = \{x \in \mathbb{R} \mid x = k\pi\}$. d) $\operatorname{sen} x = \dfrac{1}{2} = \operatorname{sen}\dfrac{\pi}{6}$. $\;S = \left\{x \in \mathbb{R} \;\middle|\; x = \dfrac{\pi}{6} + 2k\pi \text{ ou } x = \dfrac{5\pi}{6} + 2k\pi\right\}$. e) $\operatorname{sen} x = -\dfrac{\sqrt{2}}{2} = \operatorname{sen}\dfrac{5\pi}{4}$, logo $x = \dfrac{5\pi}{4} + 2k\pi$ ou $x = \pi - \dfrac{5\pi}{4} + 2k\pi$. $\;S = \left\{x \in \mathbb{R} \;\middle|\; x = \dfrac{5\pi}{4} + 2k\pi \text{ ou } x = -\dfrac{\pi}{4} + 2k\pi\right\}$. f) $\operatorname{sen} x = \dfrac{\sqrt{3}}{2} = \operatorname{sen}\dfrac{\pi}{3}$. $\;S = \left\{x \in \mathbb{R} \;\middle|\; x = \dfrac{\pi}{3} + 2k\pi \text{ ou } x = \dfrac{2\pi}{3} + 2k\pi\right\}$. g) $\operatorname{sen} x = 1 = \operatorname{sen}\dfrac{\pi}{2}$ (as duas famílias coincidem). $\;S = \left\{x \in \mathbb{R} \;\middle|\; x = \dfrac{\pi}{2} + 2k\pi\right\}$. h) $\operatorname{sen} x = -1 = \operatorname{sen}\dfrac{3\pi}{2}$. $\;S = \left\{x \in \mathbb{R} \;\middle|\; x = \dfrac{3\pi}{2} + 2k\pi\right\}$.